1. Description
Given a two-dimensional array of positive and negative integers, a sub-rectangle is any contiguous sub-array of size 1 x 1 or greater located within the whole array. The sum of a rectangle is the sum of all the elements in that rectangle. In this problem the sub-rectangle with the largest sum is referred to as the maximal sub-rectangle.
As an example, the maximal sub-rectangle of the array:
0 -2 -7 0
9 2 -6 2
-4 1 -4 1
-1 8 0 -2
is in the lower left corner:
9 2
-4 1
-1 8
and has a sum of 15.
2. Input
The input consists of an N x N array of integers. The input begins with a single positive integer N on a line by itself, indicating the size of the square two-dimensional array. This is followed by N 2 integers separated by whitespace (spaces and newlines). These are the N 2 integers of the array, presented in row-major order. That is, all numbers in the first row, left to right, then all numbers in the second row, left to right, etc. N may be as large as 100. The numbers in the array will be in the range [-127,127].
3. Output
Output the sum of the maximal sub-rectangle.
4. Example
input
4
0 -2 -7 0 9 2 -6 2
-4 1 -4 1 -1
8 0 -2
output
15
5. Code
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import java.util.Arrays; import java.util.Scanner; public class Main { public static void main(String args[]) { Scanner in = new Scanner(System.in); while(in.hasNextInt()) { int n = in.nextInt(); int[][] matrix = new int[n][n]; for(int i = 0; i < n; i++ ){ for(int j = 0; j < n; j++ ){ matrix[i][j] = in.nextInt(); } } int result = Integer.MIN_VALUE; int[] dp = new int[n]; for(int i = 0; i< n; i++){ Arrays.fill(dp, 0); for(int j = i; j< n; j++){ for(int k = 0; k< n; k++){ dp[k] +=matrix[j][k]; } result = Math.max(result, maxSubArraySum(dp)); } } System.out.println(result); } } private static int maxSubArraySum(int[] array){ int pre = 0; int sum = Integer.MIN_VALUE; for(int i = 0; i < array.length; i++ ){ if(pre < 0){ pre = array[i]; }else{ pre += array[i]; } if(sum < pre){ sum = pre; } } return sum; } }
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